There are twelve members of the mu alpha theta math team. Membership is open to all students, male and female, enrolled in Algebra 1 or higher math courses. Part A: An equation that represents the situation is

SELECT ONE

12 - b + g

b - g = 12

12 = b + g

12 - (b + g)

g + 12 = b

Part B: This equation has

a finite number of solutions

infinitely many solutions

no solutions

because

there are an unlimited number of combinations of real numbers whose sum is twelve

there are no combinations of real numbers whose sum is twelve

the number of boys or girls must be a natural number

Part C: An ordered pair that cannot be used to represent this situation is

(2, 10)

(9, 3)

(8, 4)

(7.4, 4.6)

PLEASE ALSO SHOW YOUR WORK!!!

Part A:

12 = a + b

Part B:

Infinitely many solutions  

There are unlimited number of combinations of real numbers whose sum is twelve

Part C:

(7.4, 4.6)

Step-by-step explanation:

Part A:

Let g = The number of female students in the mu alpha theta math team, and b = The number of male students in the mu alpha theta math team

The total number of students in the team = 12

Therefore, we have;

b + g = 12

Which is the same as 12 = a + b

Part B: The equation has infinitely many solutions because, there are unlimited number of combinations of real numbers whose sum is twelve

Part C: An ordered pair that cannot be used to represent this situation is (7.4, 4.6) because the number of boys and the number of girls must be natural numbers.

1/5x+9 2/5y+7

step-by-step explanation:

i think the answer is fried chicken ; >

step-by-step explanation: