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![\sqrt{3} \times \sqrt{6}\\\\\mathrm{Factor\:integer\:}6=3\times\:2\\=\sqrt{3}\times\sqrt{3\times\:2}\\\\\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}\\\\\sqrt{3\times\:2}=\sqrt{3}\times\sqrt{2}\\\\=\sqrt{3}\times\sqrt{3}\times\sqrt{2}\\\\\mathrm{Apply\:radical\:rule}:\\\quad \sqrt{a}\times\sqrt{a}=a\\\\\sqrt{3}\times\sqrt{3}=3\\\\=3\sqrt{2}](/tpl/images/0853/2354/9cfc2.png)
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Write √3*√6 in the form b√2 where b is an integer...
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