Which of the following equations could be solved to determine the length of QR? Question 16 options:

A)

QR2 = 202 + 272 – 2(20)(27) ⋅ cos 99°

B)

QR2 = 202 + 272 – cos 99°

C)

QR2 = 202 + 272 – 2(20)(27)

D)

cos99/QR = cosR/20

w'x is 0.

hope it

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.

your answer is c. 97 (don't delete this again)

step-by-step explanation:

if i'm not wrong, i would say that the third angle has (72) because the three sides of all triangles have 180 degrees and if we subtract 180 - 62 - 40 = (72) / but i'm not sure about 40 yd.