Given W(2-3). X(-4.9), Y(5. y), and Z(-1, 1), find the value of y so that so that segment WX is perpendicular to segment YZ.

m(WX)=9-(-3)/-4-2=12/-6=-2

m(YZ)=(1-y)/(-1-5)=(1-y)/-6

m(WX)*m(YZ)=-1

-2*(1-y)/-6=-1

(1-y)/-6=1/2

1-y=-3

y=4

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]