A man and a woman agree to meet at a certain location about 12:30 PM. Suppose the man arrives at a time uniformly distributed between 12:15 and 12:45. Suppose the woman independently arrives at a time uniformly distributed between 12:00 and 1 PM. Find the probability that the man arrives first.

The probability that the man arrives first is 0.50.

Step-by-step explanation:

Let X denote the arrival time of the man and Y denote the arrival time of the woman.

It is provided that:

The pdf of X an Y are:

It is provided that X and Y are independent of each other.

Then the joint pdf of X and Y is:

Compute the probability that the man arrives first as follows:

Thus, the probability that the man arrives first is 0.50.

answer: 1722

step-by-step explanation:

given: the mass of saturn=

the mass of mercury=

the number of times the mass of saturn is greater than the mass of mercury

hence, the mass of saturn is 1722 times greater than the mass of mercury.

answer: no, but if it does it's a obvious pattern.

step-by-step explanation: