If you wanted to model movements with both of the robot’s arms in the air, what function would you choose as the original model? Could you still do the same transformations with this new equation? Use the graph in the first picture to determine how to do it, and that second picture is just showing you the question from the actual worksheet (it's the last one; Part 3: Extending the Idea - #1)

answer: a

step-by-step explanation:

10.2 units

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.

1/6

step-by-step explanation: