The value of the first term of a G. P if its sum of three numbers is 7 and their product is 8.* find the gp.

Sum of three terms in a GP = 7

Product of the numbers = 8

G.P

Let the three numbers be a/r , a , ar where a is the first term and r is the common ratio.

So,

⟹ a/r + a + ar = 7 -- equation (1)

And,

⟹ (a/r) * a * ar = 8

⟹ a³ = 8

⟹ a = ³√8

⟹ a = 2

Substitute the value a in equation (1).

⟹ 2/r + 2 + 2r = 7

⟹ (2 + 2r + 2r²)/r = 7

⟹ 2 + 2r + 2r² = 7r

⟹ 2r² + 2r - 7r + 2 = 0

⟹ 2r² - 5r + 2 = 0

⟹ 2r² - 4r - r + 2 = 0

⟹ 2r(r - 2) - 1 (r - 2) = 0

⟹ (2r - 1)(r - 2) = 0

★ 2r - 1 = 0

⟹ 2r = 1

⟹ r = 1/2

★ r - 2 = 0

⟹ r = 2

If r = 1/2 ;

a/r = 2/(1/2) = 2 * 2 = 4

a = 2

ar = 2 * 1/2 = 1

If r = 2 ;

a/r = 2/2 = 1

a = 2

ar = 2 * 2 = 4

∴ Required GP is 4 , 2 , 1 or 1 , 2 , 4.

I hope it will help you.

Regards.

Step-by-step explanation:

Assume that the 4 terms are a/r, a , ar, ar2.

Product of first 3 terms = a3 =8

=> a=2

Sum of last 3 terms :

a(1 + r + r2) = 14

=> r2 + r - 6 = 0

Solving the above equation r= -3 or 2

So the terms are

-2/3, 2, -6, 18

Or

1, 2, 4, 8

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)