If ∆TIK ≅ ∆TOK and < I = (5x + 8), < K = 92, and < O is 50. What is the measure of < I?

<I = 50

Step-by-step explanation:

Sum of angles in ∆TOK is 180

Given

< I = (5x + 8),

< K = 92, and

< O is 50.

<T + <O+<K = 180

<T +92+50 = 180

<T + 142 = 180

<T = 180-142

<T = 38

Also <T+<I+<K = 180

38+5x+8+92 = 180

5x+138 = 180

5x = 42

x = 42/5

x = 8.4

Since <I = 5x+8

<I = 5(8.4)+8

<I = 42 + 8

<I = 50