the question is in the picture

the third answer

Step-by-step explanation:

f(x) = 3x + 1 works because...

x = 1

y = 4

f(x) = 3x + 1

f(1) = 3x + 1

y = 3x + 1

4 = 3(1) + 1

4 = 3 + 1

4 = 4

AND

x = 2

y = 7

f(x) = 3x + 1

f(2) = 3x + 1

y = 3x + 1

7 = 3(2) + 1

7 = 6 + 1

7 = 7

ETC...

black lol

step-by-step explanation:

h

i can tell you jamal now has 3 cookies xd

tommy has 2.

this made me lol.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.