A cattle rancher wants to enclose a rectangular area and then divide it into three pens with fencing parallel to one side of the rectangle (see the figure below). There are 510 feet of fencing available to complete the job. What is the largest possible total area of the three pens?

Step-by-step explanation:

4w + 2L = 670

2w + L = 335

L = 335 - 2w

Area A(w) = w(335 - 2w)

max occurs at the average of the solutions.

solutions are w=0 and w = 167.5

the average is 83.75

83.75 * (335 - 2 * 83.75) = 14028.125

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.

b i think

step-by-step explanation:

not really sure