1x7791789x79188037891883+8904781982 9948138481359135938581359r818581318 59135195193591359190315013959139519 5103591501059130059150105310515-15- 151-513l510510351051399103919x81209 1049115991050120-350101934501958145 1619691-1950051=?

1x7791789x79188037891883+89047819829948138481359135938581359r818581318591351951935913591903150139591395195103591501059130059150105310515-15-151-513l510510351051399103919x812091049115991050120-3501019345019581451619691-1950051= 77917897918803789188389047819829948138481359135938581359r81858131859135195193591359190315013959139519510359150105913005915010531051515151513l510510351051399103919x8120910491159910501203501019345019581451619691-1950051

Step-by-step explanation:

6.1701648e+16

Step-by-step explanation:

Sorry if i am wrong but is too many later.

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.