An object is 4900 ft above the ground. The object falls, and its height is given by the quadratic function: h(t) = −16t 2 + 4900 . The height of the object above the ground is in feet and the time, t, is in seconds. Determine when the object hits the ground.

Step-by-step explanation:

The the height of an object modeled by the function

h(t) = −16t^2 + 4900

The object hits the ground when h(t) = 0

The equation becomes:

0 = −16t^2 + 4900

-16t² = -4900

t² = 4900/16

t² = 306.25

t = √306.25

t = 17.5 secs

This means that the object hits the ground after 17.5secs

the arc length is found by finding the circumference of the full circle (2xpixradius) and then dividing by 4 to find just one quarter of the circle (90 degrees).

replication and blocking

step-by-step explanation: