if jeremiah has a course average score between 80 and 89, he will earn a grade of B in his history class. He has four previous exam scores of 69, 78, 81, and 92. The final exam score has twice the weight of each of the other exams. What range of scores on the final exam will earn Jeremiah a B in the course?

The range of scores that can earn Jeremiah a B in the course is 80 - 100

Step-by-step explanation:

Average = total scores/number of exams

For an average of 80, considering the final score has twice the weight of the previous exams;

Note: since the final score has twice the weight of previous exams, it is considered a double score and counted twice

Let the lowest final score for a B grade be y

80 = (69 + 78 + 81 + 92 + 2 * y)/6

80 * 6 = (320 + 2y)

2y = 480 - 320

y = 160/2

y = 80

Let the highest final score for a B grade be z

89 = (69 + 78 + 81 + 92 + 2 * z)/6

89 * 6 = (320 + 2z)

2z = 534 - 320

z = 214/2

z = 107

Since, the highest score in the exam cannot exceed 100,

Therefore, the range of scores that can earn Jeremiah a B in the course is 80 - 100

the multiples of 15 are 15, 30,45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195,   210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375,   390, 405, 420, 435, 450, 465, 480, 495, 510, 525, 540, 555, 570, 585, 600, 615, 630, 645, 660, 675, 690, 705, 720, and 735.

the factors of 15 are 1, 3, 5, and 15.

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step-by-step explanation: