Mrs. Dillard is installing a cubed swimming pool in her backyard. The hole that her husband dug in her backyard is 216 feet cubed. She went to the pool store to pick out a pool frame. She chose a pool frame that had a length, width, and height of 7ft. Will the pool frame she choose fit into the 216 foot cubed hole? If so, explain, if not what dimensions much she buy for the pool frame to fit?

No. The pool frame she choose will not fit into the 216 foot cubed hole. She should have picked a frame of 6ft.

Step-by-step explanation:

From the question, we are informed that Mrs. Dillard is installing a cubed swimming pool in her backyard and that the hole that her husband dug in her backyard is 216 feet cubed.

We are further told that she went to the pool store to pick out a pool frame. She chose a pool frame that had a length, width, and height of 7ft.

Since the height is 7ft, the volume will be: = 7ft × 7ft × 7ft = 343 feet cubed.

This shows that the pool frame she choose will not fit in the hole dug. She should have picked a frame of 6feet since (6ft × 6ft × 6ft) = 216 ft cubed.

x = 25

step-by-step explanation:

a^2+b^2=c^2

7^2+24^2=c^2

49+576=625

sqrt625=25

x=25

connie < felicia < stew

step-by-step explanation:

stew:

we need to find the slope

m = (y2-y1)/ (x2-x1)

    = (2650-795)/(10-3)

    = 1855/7

265 words per minute

connie:

we need to find the slope

m = (y2-y1)/ (x2-x1)

we have two points (0,0) and (4,800)

m = (800-0)/(4-0)

  m = 800/4

    200 words per minute

felicia:

260 words per minute

200< 260 < 265

connie < felicia < stew