A boy is twirling a model airplane on a string 4 feet long. If he twirls the plane at 0.5 revolutions per minute, how far does the plane travel in 4 minutes

Airplane covers a distance of approximately 50.265 feet in 4 minutes.

Step-by-step explanation:

From Rotation Physics we know that angular speed is the number of revolutions done by a particle at a given time. If the boy is twirling a model airplane at constant speed, then we calculate such variable as follows:

(Eq. 1)

Where:

- Angular speed, measured in revolutions per minute.

- Number of revolutions done by airplane, measured in revolutions.

- Time, measured in minutes.

Now we clear the number of revolutions done by airplane within expression:

If we know that and , then we get that number of revolutions is:

The airplane made two revolutions in four minutes.

Now, the distance covered by the airplane (), measured in feet, is calculated by means of the equation below:

Where:

- Length of the string, measured in meters.

- Number of revolutions done by airplane, measured in revolutions (dimensionless).

If we get that and , then the distance covered by the airplane in 4 minutes is:

Airplane covers a distance of approximately 50.265 feet in 4 minutes.

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

n

step-by-step explanation: