Complete Question
Find the range for the population mean value with 95% and 65% confidence intervals for each set of data.
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,
, ![n_2= 17](/tpl/images/0847/4862/ed4a7.png)
The range for the population mean value with 95% confidence intervals for the first set of data  is
  ![2.602](/tpl/images/0847/4862/75e7c.png)
The range for the population mean value with 95% confidence intervals for the second  set of data  is
  ![2.601](/tpl/images/0847/4862/df651.png)
The range for the population mean value with 65% confidence intervals for the first  set of data  is
 Â
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The range for the population mean value with 65% confidence intervals for the second set of data  is
 Â
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Step-by-step explanation:
Generally the range for the population mean value with 95% confidence intervals for the first set of data  is mathematically evaluated as follows
Generally the degree of freedom is mathematically evaluated as
   ![df = n_1 -1](/tpl/images/0847/4862/a7b06.png)
=> Â ![df = 24 -1](/tpl/images/0847/4862/1d65a.png)
=> Â ![df = 23](/tpl/images/0847/4862/05219.png)
From the question we are told the confidence level is  95% , hence the level of significance is  Â
   ![\alpha = (100 - 95 ) \%](/tpl/images/0847/4862/c759c.png)
=> Â ![\alpha = 0.05](/tpl/images/0847/4862/246a1.png)
Generally from the t distribution table the critical value  of   at  is Â
  ![t_{\frac{\alpha }{2} , df = 23} = 2.068](/tpl/images/0847/4862/d612b.png)
Generally the margin of error is mathematically represented as Â
   ![E_1 = t_{\frac{\alpha }{2} , df = 23} * \frac{\sigma_1 }{\sqrt{n_1} }](/tpl/images/0847/4862/20adb.png)
=> Â
Â
=> Â ![E_1 = 0.00844](/tpl/images/0847/4862/d6126.png)
Generally 95% confidence interval is mathematically represented as Â
   ![\= x_1 -E_1 < \mu < \=x_1 +E_1](/tpl/images/0847/4862/6c863.png)
    ![2.611 - 0.00844 < \mu < 2.611 + 0.00844](/tpl/images/0847/4862/a4971.png)
=> Â ![2.602](/tpl/images/0847/4862/f0aae.png)
Generally the range for the population mean value with 95% confidence intervals for the second set of data  is mathematically evaluated as follows
Generally the degree of freedom is mathematically evaluated as
   ![df_2 = n_2 -1](/tpl/images/0847/4862/9fd95.png)
=> Â ![df_2 = 17 -1](/tpl/images/0847/4862/c2248.png)
=> Â ![df_2 = 16](/tpl/images/0847/4862/16f55.png)
From the question we are told the confidence level is  95% , hence the level of significance is  Â
   ![\alpha = (100 - 95 ) \%](/tpl/images/0847/4862/c759c.png)
=> Â ![\alpha = 0.05](/tpl/images/0847/4862/246a1.png)
Generally from the t distribution table the critical value  of   at  is Â
  ![t_{\frac{\alpha }{2} , df = 16} = 2.12](/tpl/images/0847/4862/6ec37.png)
Generally the margin of error is mathematically represented as Â
   ![E_1 = t_{\frac{\alpha }{2} , df = 23} * \frac{\sigma_2 }{\sqrt{n_2} }](/tpl/images/0847/4862/a6202.png)
=> Â
Â
=> Â ![E_2 = 0.03085](/tpl/images/0847/4862/65339.png)
Generally 95% confidence interval is mathematically represented as Â
   ![\= x_2 -E_2 < \mu < \=x_2 +E_2](/tpl/images/0847/4862/7244f.png)
    ![2.632 - 0.03085](/tpl/images/0847/4862/9b75e.png)
=> Â ![2.601](/tpl/images/0847/4862/df651.png)
Generally the range for the population mean value with 65% confidence intervals for the first set of data  is mathematically evaluated as follows
Generally the degree of freedom is mathematically evaluated as
   ![df = n_1 -1](/tpl/images/0847/4862/a7b06.png)
=> Â ![df = 24 -1](/tpl/images/0847/4862/1d65a.png)
=> Â ![df = 23](/tpl/images/0847/4862/05219.png)
From the question we are told the confidence level is  95% , hence the level of significance is  Â
   ![\alpha = (100 - 65 ) \%](/tpl/images/0847/4862/bf3f5.png)
=> Â ![\alpha = 0.35](/tpl/images/0847/4862/c5b1f.png)
Generally from the t distribution table the critical value  of   at  is Â
  ![t_{\frac{\alpha }{2} , df = 23} = 1.3995](/tpl/images/0847/4862/67c41.png)
Generally the margin of error is mathematically represented as Â
   ![E_3 = t_{\frac{\alpha }{2} , df = 23} * \frac{\sigma_1 }{\sqrt{n_1} }](/tpl/images/0847/4862/47790.png)
=> Â
Â
=> Â ![E_3 = 0.00571](/tpl/images/0847/4862/2e857.png)
Generally 95% confidence interval is mathematically represented as Â
   ![\= x_1 -E_3 < \mu < \=x_1 +E_3](/tpl/images/0847/4862/b8e0c.png)
    ![2.611 - 0.00571](/tpl/images/0847/4862/8b563.png)
=> Â
Â
Generally the range for the population mean value with 65% confidence intervals for the second set of data  is mathematically evaluated as follows
Generally the degree of freedom is mathematically evaluated as
   ![df_2 = n_2 -1](/tpl/images/0847/4862/9fd95.png)
=> Â ![df_2 = 17 -1](/tpl/images/0847/4862/c2248.png)
=> Â ![df_2 = 16](/tpl/images/0847/4862/16f55.png)
From the question we are told the confidence level is  95% , hence the level of significance is  Â
   ![\alpha = (100 - 65 ) \%](/tpl/images/0847/4862/bf3f5.png)
=> Â ![\alpha = 0.35](/tpl/images/0847/4862/c5b1f.png)
Generally from the t distribution table the critical value  of   at  is Â
  ![t_{\frac{\alpha }{2} , df = 16} = 1.41930](/tpl/images/0847/4862/ff6cc.png)
Generally the margin of error is mathematically represented as Â
   ![E_4 = t_{\frac{\alpha }{2} , df = 23} * \frac{\sigma_2 }{\sqrt{n_2} }](/tpl/images/0847/4862/fbeeb.png)
=> Â
Â
=> Â ![E_4 = 0.020653](/tpl/images/0847/4862/42f1c.png)
Generally 95% confidence interval is mathematically represented as Â
   ![\= x_2 -E_4 < \mu < \=x_2 +E_4](/tpl/images/0847/4862/24887.png)
    ![2.632 - 0.020653](/tpl/images/0847/4862/f64bb.png)
=> Â
Â