Mathematics, 28.10.2020 16:40 richierichMBM7786
F(x)=(3x-5)^3f(x)=(3xβ5) 3 f, left parenthesis, x, right parenthesis, equals, left parenthesis, 3, x, minus, 5, right parenthesis, cubed h(x)=2\sqrt[3]{x}+8h(x)=2 3 x +8h, left parenthesis, x, right parenthesis, equals, 2, cube root of, x, end cube root, plus, 8 Write h(f(x))h(f(x))h, left parenthesis, f, left parenthesis, x, right parenthesis, right parenthesis as an expression in terms of xxx.
Answers: 1
![f(x) = (3x-5)^3\\h(x) = 2\sqrt[3]{x}+8](/tpl/images/0847/4850/92d86.png)
in terms of x
, we will replace x in h(x) with (3x-5)Β³ as shown:![h((3x-5)^3) = 2\sqrt[3]{(3x-5)^3} +8\\ h((3x-5)^3) = 2(3x-5) + 8\\ h((3x-5)^3) = 6x - 10 + 8\\ h((3x-5)^3) = 6x-2\\Hence \ h(f(x)) =6x-2](/tpl/images/0847/4850/1b885.png)
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F(x)=(3x-5)^3f(x)=(3xβ5) 3 f, left parenthesis, x, right parenthesis, equals, left parenthesis, 3, x...
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