The sum of 3 numbers in an ap is -3 and their product is 24 find the number

• Sum of three numbers in an AP is -3

• Their product is 24.

• The numbers .

Let the numbers be .

• (a-d) , a , (a+d) .

A/Q ,

• Sum of numbers = -3

=> a-d + a + a+d = -3

=> 3a= -3

=> a = -1 .

Now ,

• Product of numbers = 24

=>( a-d)(a)(a+d)= 24

=> (a²- d²) (a) = 24

=> (1- d²)(-1)=24

=> -1+d²= 24

=> d²= 25

=> d = ±5.

If d = 5 the numbers are :

• a+d , a , a-d = 4 , -1 , -6

If d = -5 the numbers are :

• a+d , a , a -d = -6, -1 , 4 .

The numbers are :

4 , -1 , -6 and -6, -1,4

I hope it will help you.

Regards.