you invest 10,000 dollars into two accounts, one earning 5% interest and the other earning 8% interest. If the total annual interest earned is 590 dollars, how much do you invest into each account? PLZ SHOW WORK

$7,300 was invested in the 14% account while $2,700 was invested in the 8% interest account

Step-by-step explanation:

Let the amount invested in first account be $x while the amount for second account is $y

Mathematically;

x + y = 10,000 •••••••••(i)

Interest on first account

= 14% of x = 14/100 * x

Interest on second account

= 8% of y= 8/100 * y

Adding all together will give total

14/100 * x + 8/100 * y = 1238

Multiply through by 100

14x + 8y = 123800 •••••••(ii)

From equation 1, x = 10,000 - y

Insert this into second equation

14(10,000-y) + 8y = 123,800

140,000 - 14y + 8y = 123,800

140,000 - 6y = 123,800

6y = 140,000 - 123,800

6y = 16,200

y = 16,200/6

y = $2,700

Recall

x + y = 10,000

x = 10000 - y

x = 10,000 - 2,700

x = $7,300

Step-by-step explanation:

Hope this helps :)

25 questions , because they start with 100.  

350-100=250 .  

. 250/10=25

step-by-step explanation:

first take off 100, then what x 10 = 250? that is your answer. (25)

investment b is an ordinary annuity with $3,909.64 in the account after one year.

step-by-step explanation: