2.) What is the perimeter of a polygon with vertices at (-3, 1), (5, 1), (-3, 4), (5, 4)?

33.1 units

Step-by-step explanation:

The formula to find the sides of an shape when given vertices is

= √(x2 - x1)² + (y2 - y1)²

When we have:(x1, y1) and (x2, y2)

(-3, 1), (5, 1), (-3, 4), (5, 4)

For (-3, 1), (5, 1)

= √(5 - (-3))² + (1 -1)²

= √8² + 0²

= √64

= 8 units

For (5, 1), (-3, 4)

= √(-3 - 5)² + (4 - 1)²

= √-8² + 3²

= √64 + 9

= √73 units

For (-3, 4), (5, 4)

= √(5 - (-3))² + (4 - 4)²

= √8² + 0²

= √64

= 8 units

For (-3, 1), (5, 4)

= √(-3 - 5)² + (4- 1)²

= √8² + 3²

= √64 + 9

= √ 73 units

Perimeter of the Polygon:

=( 8 + √73 + 8 + √73) units

= 33.088007491 units

≈ 33.1 units

step-by-step explanation:

just plug in each number for x and see which ones work and don't

answer: ouch. thats difficult

step-by-step explanation: