Does anyone know how to do this??

Step-by-step explanation:

i'll explain how to do 9), it is the same process for the rest

y = 2x - 1

thus the value of 'y' should be the same as the result of '2x - 1'

when x = 5, 2x - 1 = 2(5) - 1 = 9, Thus (x, y) = (5, 9)

when x = 2, 2x - 1 = 2(2) - 1 = 3 Thus (x, y) = (2, 3)

when x = 0, 2x - 1 = 2(0) - 1 = 1 Thus (x, y) = (0, 1)

so in the table we have

x        2x - 1      y         (x, y)

5          9          9         (5, 9)

2          3          3         (2, 3)

0          1           1          (0, 2)

we can now plot these values on a graph to look like so

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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