A football team has an away game, and the bus breaks down. The coaches decide to drive the players to the game in cars and vans. Four players can ride in each car. Six players can ride in each van. There are 48 players on the team. The equation 4.3 + 6y = 48
models this situation, where x is the number of cars and y is the number of vans

Question:

Find 4 possible solutions in the context of the problem.

The 4 possible solutions in the context of the problem are (0, 8), (3, 6), (6, 3), and (9, 2)

Given the equation that models the situation expressed as:

4x + 6y = 48

We are to find 4 possible solutions for x and y. Note that the values of x and y must be integers.

If there are no cars i.e. at when x = 0

4(0) + 6y = 48

0 + 6y = 48

6y = 48

y = 48/6

y = 8

One of the solution is (0, 8)

If there are 3 cars, i.e. at when x = 0

4(3) + 6y = 48

12 + 6y = 48

6y = 48 - 12

y = 36/6

y = 6

The second solution will be (3, 6)

If there are 6 cars, i.e. at when x = 6

4(6) + 6y = 48

24 + 6y = 48

6y = 48 - 24

y = 24/6

y = 4

The third solution will be (6, 3)

If there are 9 cars, i.e. at when x = 9

4(9) + 6y = 48

36 + 6y = 48

6y = 48 - 36

y = 12/6

y = 2

The fourth solution will be (9, 2)

Hence the 4 possible solutions in the context of the problem are (0, 8), (3, 6), (6, 3), and (9, 2)

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Answer     2x and 7y

Step-by-step explanation:

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

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