Write an equation of the line passing through the point (8,-5) that is parallel to the line 2x – 6y=-3. y = mx + b

y=x -

Step-by-step explanation:

Ist put the first equation in y=mx+b form

2x-6y=-3

subtract 2x on both sides

2x-6y=-3

-2x    =-2x

-6y=-2x-3

then divide both sides by -6

-6y=-2x-3

-6

that gives y=x+for the original equation

Then plug in the point and slope in y=mx+b

Use the same slope since the lines are parallel

(-5)=()(8)+b

-5=+b

then subtract 8/3 on both sides and that gives

-23/3 = b

then you can make the new equation using -23/3 for you b and 1/3 for your slop m

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

14

step-by-step explanation: