Suppose you are playing a game of chance. if you bet $5 on a certain event, you will collect $115 (including your $5 bet) if you win. find the odds used for determining the payoff

So if you loss the game, you lose $5, if you win, you win 110$ (not considering the 5$ you pay).

the relation between this numbers is 110/5 = 22.

so if you win, you are winning 22 times the money you are paying.

this means that in this game you should have a 1/22 (or a 4.5%) odds to win

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

4 and 5)16.97 or 12√2

6)15.59 or 9√3

7)y = 15.59 or 9√3     x =27

8)17.80