If the probability of a chance event is 0.67, it is less likely to happen than which of the following probabilities of another chance event? 0.65

0.76

0

0.61

Which expression is equivalent to 8(k + m) − 15(2k + 5m)?

Express in the simplest form: (x^2+9x+14/x^2-49) / (3x+6/x^2+x-56)

Prove (a) cosh2(x) − sinh2(x) = 1 and (b) 1 − tanh 2(x) = sech 2(x). solution (a) cosh2(x) − sinh2(x) = ex + e−x 2 2 − 2 = e2x + 2 + e−2x 4 − = 4 = . (b) we start with the identity proved in part (a): cosh2(x) − sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 − sinh2(x) cosh2(x) = 1 or 1 − tanh 2(x) = .