4. A foreign student club lists its members as 3 Chinese, 3 Brazilians, 4 Columbians, 2 Ghanaians. If a committee of 4 people are selected at random, what is the probability that all nationalities are represented

0.1454545455

Step-by-step explanation:

We solve using the combination formula

C(n, r) = nCr

= n!/r!(n - r)!

Hence, the probability that all nationalities are represented, is choosing 1 of each nationality.

Hence, we have:

3 Chinese, 3 Brazilians, 4 Columbians, 2 Ghanaians.

Total number of people = 3 + 3 + 4 + 2 = 12

= 3C1 × 3C1 × 4C1 × 2C1 /12C4

= 3 × 3 × 4 × 2/495

= 72/495

= 0.1454545455

The probability that all nationalities are represented is 0.1454545455

choice b is correct

step-by-step explanation:

we have been given the following system of inequalities;

we are required to graph the solution to the system of inequalities. using a graphing tool, the graph of the system is as shown in the attachment. the continuous line represents the graph of while the dotted line represents .

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x