Please explain your answers! Will pick brainliest

A. x=-40

I don't know if there is supposed to be a b

C.x= 23/22

Step-by-step explanation:

Simplify   —

           2

Equation at the end of step

1

:

     3       1

 (6+(—•x))-((—•x)-4)  = 0

     4       2

STEP

2

:

Rewriting the whole as an Equivalent Fraction

2.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  2  as the denominator :

        4     4 • 2

   4 =  —  =  —————

        1       2  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

x - (4 • 2)     x - 8

———————————  =  —————

     2            2  

Equation at the end of step

2

:

        3          (x - 8)

 (6 +  (— • x)) -  ———————  = 0

        4             2  

STEP

3

:

           3

Simplify   —

           4

Equation at the end of step

3

:

        3          (x - 8)

 (6 +  (— • x)) -  ———————  = 0

        4             2  

STEP

4

:

Rewriting the whole as an Equivalent Fraction

4.1   Adding a fraction to a whole

Rewrite the whole as a fraction using  4  as the denominator :

         6     6 • 4

    6 =  —  =  —————

         1       4  

Adding fractions that have a common denominator :

4.2       Adding up the two equivalent fractions

6 • 4 + 3x     3x + 24

——————————  =  ———————

    4             4  

Equation at the end of step

4

:

 (3x + 24)    (x - 8)

 ————————— -  ———————  = 0

     4           2  

STEP

5

:

STEP

6

:

Pulling out like terms

6.1     Pull out like factors :

  3x + 24  =   3 • (x + 8)

Calculating the Least Common Multiple :

6.2    Find the Least Common Multiple

     The left denominator is :       4

     The right denominator is :       2

       Number of times each prime factor

       appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

2212

Product of all

Prime Factors  424

     Least Common Multiple:

     4

Calculating Multipliers :

6.3    Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M

   Denote the Left Multiplier by  Left_M

   Denote the Right Multiplier by  Right_M

   Denote the Left Deniminator by  L_Deno

   Denote the Right Multiplier by  R_Deno

  Left_M = L.C.M / L_Deno = 1

  Right_M = L.C.M / R_Deno = 2

Making Equivalent Fractions :

6.4      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      3 • (x+8)

  ——————————————————  =   —————————

        L.C.M                 4    

  R. Mult. • R. Num.      (x-8) • 2

  ——————————————————  =   —————————

        L.C.M                 4    

Adding fractions that have a common denominator :

6.5       Adding up the two equivalent fractions

3 • (x+8) - ((x-8) • 2)     x + 40

———————————————————————  =  ——————

           4                  4  

Equation at the end of step

6

:

 x + 40

 ——————  = 0

   4  

STEP

7

:

When a fraction equals zero

7.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 x+40

 ———— • 4 = 0 • 4

  4  

Now, on the left hand side, the  4  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  x+40  = 0

Solving a Single Variable Equation:

7.2      Solve  :    x+40 = 0

Subtract  40  from both sides of the equation :

                     x = -40

One solution was found :

x = -40

sorry its so long

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.