Tris has two times as many quarters as dimes and three more nickels than dimes. If he has a total of $3.40, how many of each coin does he have?

Janet has 12 dimes, 4nickels, and 8 quarters.

Step-by-step explanation:

Let N be the number of nickels

So she has 3N dimes =6N nickels and 2N quarters. So 2N q= 2x5=10N nickels. (1quarter=25 c and 1 nickel=5 cents, so 1 q=5 n)

So in all she has 6N+N+10N=17 N nickels

$3.40= 340 cents. = 17xNx5 cents. So N =4.

step-by-step explanation:

i could only see the first page. the other pages were blurry. ; -;

x hot dogs for 2$, y drinks for 3$. 29 items and total 70

2x+3y=70

x+y=29

if x=17and y=12

2(17)+3(12)=70

34+36=70