Can someone please answer this!! There is an equilateral triangle with an area of 4√3 cm². What is the measure of one of the sides. Show your work for credit.

4cm

I wrote on paper as well to be more specific.

Step-by-step explanation:

The formula that determines the area of a equilateral triangle is (√3/4)*a^2

where a is the side of triangle.

so 4√3=(√3/4)*a^2

(4√3)/(√3/4)=a^2

((4√3)*4)/√3=a^2

16=a^2

a=√16

a=4

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92