Enter the ordered pair for the vertices for (Ry-axis o T(2,0))(QRST).

Q' = (-3, 3)

R' = (-5, -3)

S' = (-2, -2)

T' = (0, 1)

Step-by-step explanation:

The coordinates of the vertices of the quadrilateral are;

T(-2, 1), Q(1, 3), S(0, -2), R(3, -3)

Therefore, taking the operation on the right first, we have;

T(2, 0)QRST, gives;

T(2, 0)QRST→ T(-2 + 2, 1), Q(1 + 2, 3), S(0 + 2, -2), R(3 + 2, -3)

T(2, 0)QRST→ T(0, 1), Q(3, 3), S(2, -2), R(5, -3)

For the next process R y-axis which is the reflection about the y-axis, the preimage (x, y) becomes the image (-x, y)

Therefore, we have;

R y-axis(T(0, 1), Q(3, 3), S(2, -2), R(5, -3)) = T'(0, 1), Q'(-3, 3), S'(-2, -2), R'(-5, -3)

From which we get (Ry-axis T(2, 0))(QRST =  T'(0, 1), Q'(-3, 3), S'(-2, -2), R'(-5, -3).

the cat is blue because the probability of extension towards the prefix of the diameter of the circle could only mathematically equal to the sum of the roots of the carrots from   your garden.

step-by-step explanation:

a: 1/6, j: 1/4

step-by-step explanation: you are welcome