A ball is thrown from an initial height of 1 meter with an initial upward velocity of 20 m/s. The ball's height h (in meters) after t seconds is given by the following
h = 1+200-512
Find all values of t for which the ball's height is 11 meters.
Round your answer(s) to the nearest hundredth.
(If there is more than one answer, use the "or" button.)

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8

step-by-step explanation:

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the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!