There are 23 students in an MA 206 class at FCC. How many ways are there to select 5 students for a group project?

Step-by-step explanation:

We are expected to use the combination method to solve for the number of ways

given that

number of students n= 23

number of groups r= 5

the expression for the number of ways is given as

C(n,r)= n!/r!(n-r)!

substituting we have

C(23,5)= 23!/r!(n-r)!

C(23,5)= 23!/5!(23-5)!

C(23,5)= 23!/5!(18)!

C(23,5)= 23*22*21*20*19*18!/5!(18)!

C(23,5)= 23*22*21*20*19/5!

C(23,5)= 23*22*21*20*19/5*4*3*2*1

C(23,5)= 23*22*21*20*19/120

C(23,5)= 4037880/120

              33649ways

you cant answer this dummy

step-by-step explanation:

i belive those are the ones that are under 90 degreese.