Find the probability that a person is audited more than twice. (Round your answer to four decimal places.)

Complete Question

The chance of an IRS audit for a tax return with over $25,000 in income is about 2% per year. We are interested in the expected number of audits a person with that income has in a 9-year period. Assume each year is independent.

Find the probability that a person is audited more than twice. (Round your answer to four decimal places.)

The probability is  

Step-by-step explanation:

From the question we are told that

The  probability of an IRS audit for a tax return with over $25,000 in income is p= 0.02

The sample size  n  =  9

Generally the distribution of IRS audit for a tax return follows a binomial distribution  

i.e  

and the probability distribution function for binomial  distribution is  

Here C stands for combination hence we are going to be making use of the combination function in our calculators  

Generally the probability that a person is not audited at all is mathematically

Generally the probability that a person is  audited once  is mathematically

Generally the probability that a person is  audited twice is mathematically represented

Generally the probability that a person is audited more than twice is mathematically represented

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answer: okw

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°