The heart rates in beats per minute for runners who walk briskly on a treadmill for 6 minutes follow a Normal distribution with a mean of 104 and standard deviation of 12.5. What percent of the runners have heart rates above 140?

0.2%

Step-by-step explanation:

We apply the z score formula.

This is given as:

Z score = x - μ/σ

x = Raw score = 140

μ = Population mean = 104

σ = Standard deviation = 12.5

z = 140 - 104/12.5

z = 2.88

Probability value from Z-Table:

P(x<140) = 0.99801

P(x>140) = 1 - P(x<140)

= 1 - 0.99801

= 0.0019884

Approximately = 0.0020

Converting to percent = 0.2%

Therefore, percent of the runners have heart rates above 140 is 0.2%

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages

hello,

as we don't know if g(x) is continue,

answer b

f(x)=2x²-8x+1=2(x²-4x+4)+1-8=2(x-2)²-7

vertex is (2,-7) ( a minimum since coefficient of x² is > 0)