The mean weight of an adult is 6565 kilograms with a standard deviation of 1313 kilograms. If 9292 adults are randomly selected, what is the probability that the sample mean would be greater than 62.762.7 kilograms

0.9554

Step-by-step explanation:

Let be the sample mean.

Given: Mean weight of an adult is 65 kilograms with a standard deviation of 13 kilograms.

Sample space = 92

The probability that the sample mean would be greater than 62.7 kilograms:

[ By p-value table]

Hence, the required probability= 0.9554

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

expression #3 is not equivalent. the others are.