–2x + 2y = 6
4x +2y=-5

To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

-2x+2y=6,4x+2y=-5

Choose one of the equations and solve it for x by isolating x on the left hand side of the equal sign.

-2x+2y=6

-2x=-2y+6

x=-\frac{1}{2}\left(-2y+6\right)

x=y-3

4\left(y-3\right)+2y=-5

4y-12+2y=-5

6y-12=-5

6y=7

y=\frac{7}{6}

Step-by-step explanation:

x=\frac{7}{6}-3

x=-\frac{11}{6}

x=-\frac{11}{6},y=\frac{7}{6} the answer

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

i think this could be a possible answer (1 / 84) -1

good luck! : d