The sum of three consecutive ODD integers is 105. What is the value of the SMALLEST?

33

Step-by-step explanation:

The difference between two consecutive odd integers is 2.

Let the smallest odd integer be x.

The next greater odd integer is x + 2.

The next greater odd integer is 2 more than the second one, so it is

x + 2 + 2 = x + 4.

The 3 odd integers are x, x + 2, x + 4.

Add them and set the sum equal to 105. Then solve for x.

x + x + 2 + x + 4 = 105

3x + 6 = 105

3x = 99

x = 33

The smallest of the 3 integers is 33.

the answer is 48m^2!

step-by-step explanation: