HEY can someone PLEASE help me and show how you got the answer quick i’m in an exam

ok so first you gotta find y

first step

7y+3+3y-5=9y+7

second step (part a)

10y+3-5=9y+7

second step (part b)

10y-2=9y+7 (since there was negative 5 and 5 was bigger our answer will be in negative)

third step

10y-9y=7+2

fourth step (part a)

1y=7+2

fourth step (part b)

1y=9

fifth step

y=9

ok now tht u got the y

the second part will be ez

now i will be doing b

GI=9× 9+7

81+7

88

Step-by-step explanation:

explanation for the first step: since GH+HI=GI our equation will be 7y+3+3y-5=9y+7

explanation for the second step( part a)

add all the numbers which has y with one another

explanation for the second step (part b)

add all the numbers which are without the y

( do not do the one after the equal sign (=) )

explanation for the third step

we move all the y in one side ( with their number ofc)

and all the numbers without y to the other

(obv the sign changes when u move them)

explanation for the fourth step (part a)

we add them ( all the y together)

explanation for the fourth step (part b)

we add them ( all the number without y)

explanation for the fifth step

we remove 1 cz 1y=y

now i will be doing b

explanation for the first step (for q b)

since y=9

we will replace y with 9

explanation for the second step (for q b)

as the rule of math we will do the multiplication first

and 9× 9=81

explanation for the third step

add 81 and 7

a) y= 9

b) GI= 88

hope this help and hope I explained everything

yw:

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf = 

pf = 6,25 u

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step-by-step explanation:

answer: 10 turtles

step-by-step explanation: as turtles have four legs so 4.10=40 therefore birds are 4 which sue counted