What are the coordinates of the vertices of a dilation for triangle ABC at A (-1,-1) B(4,0) and C(2,3). A'B'C' with scale factor 2.5 centered at the origin?

The coordinates of the image of Δ ABC are:

A' (-2.5, -2.5), B' (10, 0), C' (5, 7.5)

Step-by-step explanation:

Let us revise the rule of dilation

If the point (x, y) dilated by scale factor k centered at the origin, then the image of the point is (k x, k y)

We will use this rule to solve the question

∵ The vertices of triangle ABC are A (-1, -1), B (4, 0), C (2, 3)

∵ The scale factor of a dilation is 2.5

∴ k = 2.5

∵ The center is the origin

→ That means multiply each coordinate of the points by 2.5

∴ A' = (-1 × 2.5, -1 × 2.5)

∴ A' = (-2.5, -2.5)

∴ B' = (4 × 2.5, 0 × 2.5)

∴ B' = (10, 0)

∴ C' = (2 × 2.5, 3 × 2.5)

∴ C' = (5, 7.5)

The coordinates of the image of Δ ABC are:

A' (-2.5, -2.5), B' (10, 0), C' (5, 7.5)

if the pizza is divided equally into 2 equal halves then you would get

πr^2/2

where r is the radius of the pizza.

happy to

pls mark as brainliest