How do you do this question?

Conditionally convergent

Step-by-step explanation:

Use alternating series test.

bₙ = n / √(n³ + 9)

lim(n→∞) bₙ

= lim(n→∞) [n / √(n³ + 9)]

= lim(n→∞) (n / √n³)

= lim(n→∞) (1 / √n)

= 0

The limit is 0, and bₙ is a decreasing series, so ∑aₙ converges.

Since bₙ > 1/n for n > 2, and 1/n diverges, ∑bₙ diverges.

(Alternatively, we could use limit comparison test to compare bₙ to n/√n³ and show that both diverge.)

Therefore, ∑aₙ is conditionally convergent.

dont think so

step-by-step explanation:

answer: (-6,3)

step-by-step explanation: