Given the function x^3-5x:
Find f (2)
Find f(-2)
Is the function odd or even?

f(2)= -2, f(-2)= 2, odd

Step-by-step explanation:

1. f(2)=x^3-5x

2. f(2)= 2^3-5(2)

3. f(2)=8-10

4. f(2)= -2

5. f(-2)= x^3-5x

6. f(-2)= -2^3-5(-2)

7. f(-2)= -8+10

8. f(-2)= 2

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this