1. (x + 2y)2 + (x - 2y) Step 1: (x + 2y)2 = x2 + 4xy + 4y2
Step 2: (x - 2y)2 = x2 - 4xy + 4y?
Step 3: (x2 + 4xy + 4y?) + (x2 - 4xy + 4y?) = 2x2 + 8y2
What special products were used to solve the problem?
Aside from multiplication, what other algebraic processes did you use to solve the
problem?
2.
[(3x) (2x) - (2y)(-4y)]
Step 1: (3x) (2x) = 6x
Step 2:
Step 3:
Step 4:
Multiply the subtrahend.
Combine like terms.
Square the binomial.
What special products were used to solve the problem?

i need the table so i can see

step-by-step explanation:

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

for this case we have that by definition, the surface area of a cylinder is given by:

where:

r: it is the radius of the cylinder

h: it is the height of the cylinder

we can also rewrite it as:

where:

la: it's the lateral area

ba: area of the base

option a