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Find an equation (in term of x) of line through the points (-1,3) and (1,4)
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If sec theta = 5/3 and the terminal point determined by theta is in quadrant 4, then
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Select the conic section that represents the equation. 3x2 + 3y2 -2x + 4 = 0
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Graph the line with the given slope m and y-intercept b. m=-3,b=1
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