On a coordinate plane, a line goes through points (negative 2, 1) and (0, negative 3). Y = negative StartFraction 2 Over 9 EndFraction x + 2. Two separate linear functions are expressed by the graph and by the equation. Select all that apply.

The slope is negative for both functions.
The equation has a steeper slope than the line in the graph.
The slope of the line in the graph is -2.
The graph and the equation express an equivalent function.

answer: answer is c!

ok i got to organize the

3/15 and 12/55

3*

aha

3*4 equals 12 but not

a: no

b:

8/24 12/35

no

gautie

it's c

5/18 = 25/90

5*5=25

18*5 = 90

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< 3

step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

50x5=$250

step-by-step explanation: