what is an equation in point slope form the line that passes through the point (-2, 10) and has slope-4?

An equation in point-slope form of a line that passes through the point (-2, 10) and has slope -4 is; (y - 10) = -4(x + 2).

The point-slope form of the equation of a line takes the form;

(y - b) = m(x + a).

where m = slope

In this case; m = -4; a = -2; and b = 10.

The equation is therefore; (y - 10) = -4(x + 2).

Read more;

link

 y-10 = -4(x+2)  

in slope-intercept form, it would be  y = -4x + 2

Step-by-step explanation:  point-slope form:

y - b = m(x - a)    

a is the given x-coordinate,  b is the given y-coordinate  m is the slope

Substitute the given values into the formula

y - 10 = -4( x- -2)

change -(-2) to +2 to simplify  

y-10 = -4(x+2)  

kk.bj.

step-by-step explanation:

.mnm.kn.kj

answer: 42

use a calculator to find that 845/73 = 11.575

the whole part of the answer is 11. multiply this by 73 to get 11*73 = 803.

subtract that result from 845 to get 845 - 803 = 42