PLEASE HELP WILL GIVE BRAINLIEST m∠A = _˚

m∠B = _˚

m∠C = _˚

m∠X = _˚

m∠Y = _˚

m∠Z = _˚

Segment AB = _ units

Segment BC = _ units

Segment AC = _ units

Segment XY = _ units

Segment YZ = _ units

Segment XZ = _ units

the answers are...

segment FE over segment XY equals segment EG over segment YZ equals segment GF over segment ZX

see the attached figure to better understand the problem

we know that

If m∠E = m∠Y and m∠F = m∠X

then

Triangles EFG and YXZ are similar by AA Similarity Theorem

Remember that

If two figures are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

In this problem

The corresponding sides are

FE and XY

EG and YZ

GF and ZX

so

therefore

segment FE over segment XY equals segment EG over segment YZ equals segment GF over segment ZX

have a blessed bay <3 <3 <3

Step-by-step explanation:

4

step-by-step explanation: