What is the slope of a line that is perpendicular to the graph of y=1/6x+8 ?
Select one:
-6

6

1/6

-1/6

A. -6

Step-by-step explanation:

The slope of the line that is perpendicular to the graph y = ⅙x + 8, is a negative reciprocal of the slope of the graph, y = ⅙x + 8.

What this means is that, if you multiply the slope of y = ⅙x + 8, and the slope of the line perpendicular to it, you would have -1. That is .

Where,

= slope of y = ⅙x + 8.

= slope of the line perdendicular to y = ⅙x + 8.

The slope of y = ⅙x + 8 is ⅙.

Substitute = ⅙ into , to find the slope of the line that is perpendicular to the graph of y = ⅙x + 8.

Multiply both sides by 6

The slope of the line that is perpendicular to the graph of y = ⅙x + 8 is -6.

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.