In an experiment the temperature of at 16.9°C is decreasing at a rate of 2.3°C per minute and the temperature of a solid at 30.7°C is decreasing at a rate of 6.9°C per minute enter the number of minutes it will take a liquid and solid to reach the same temperature

The number of minutes it will take for a liquid and a solid to reach the same temperature is 3 minutes.

Step-by-step explanation:

You know that the temperature of liquid at 16.9°C is decreasing at a rate of 2.3°C per minute. Then, the temperature of the liquid after t minutes, as its value decreases, will be the difference between the initial temperature of 16.9 ° C and the temperature after t minutes. So:

temperature of the liquid= 16.9°C - 2.3 °C/minute * t

On  the other  side, you know that the temperature of a solid at 30.7°C is decreasing at a rate of 6.9°C per minute. Then, the temperature of the solid after t minutes, as its value decreases, will be the difference between the initial temperature of 30.7°C and the temperature after t minutes. So:

temperature of the solid= 30.7°C - 6.9 °C/minute * t

You want to calculate the number of minutes it will take for a liquid and a solid to reach the same temperature. This is:

temperature of the liquid= temperature of the solid

16.9°C - 2.3 °C/minute * t= 30.7°C - 6.9 °C/minute * t

Solving:

- 2.3 °C/minute * t= 30.7°C - 6.9 °C/minute * t - 16.9°C

- 2.3 °C/minute * t + 6.9 °C/minute *t= 30.7°C - 16.9°C

4.6 °C/minute * t = 13.8 °C

t=3 minutes

So the number of minutes it will take for a liquid and a solid to reach the same temperature is 3 minutes.

#15. square

step-by-step explanation:

because quadrilatural (idk how to spell it) means somthing that is not 3d or like, equal sides (or somthing like that   you know what i meanz)

hope this halps!

bai!

uhhh idk u yolo?