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How do you create a data set with 8 points in it that has a mean of approximately 10 and a standard deviation of approximately 1?
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1. evaluate 8x(2)y9(-2) for x=-1 and y=2 2. simplify the equation. -() 3. simplify the expression. [tex]\frac{5}{x(-2) y9(5)}[/tex]
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The expression x(x+4)+6(x+4) is equalivant to...
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