Juan writes the expression below to determine the total cost of 1 sandwich and n side dishes. 10 . 50 + 1 . 50 ( n − 1 ) Juan orders a sandwich and the same number of side dishes each of the five days this week. All together, Juan pays $75 for these 5 lunches. Write an equation that can be used to find the number of side dishes Juan orders for lunch this week.

She has  n= 4 side dishes.

Total side dishes ordered = 5n = 20

Step-by-step explanation:

The total cost is given by

TC= 10 . 50 + 1 . 50 ( n − 1 )

She orders same 5 lunches for $ 75

$ 75= 5{ 10 . 50 + 1 . 50 ( n − 1 ) }

Or

Cost of 1 lunch would be $ 15

$ 75/5 = { 10 . 50 + 1 . 50 ( n − 1 ) }

or

$ 15 = 10 . 50 + 1 . 50 ( n − 1 )

$ 15-$  10 . 50 = 1 . 50 ( n − 1 )  

$ 4.5/ 1.5= n-1

$ 3= n-1

3+1= n

n= 4

She has  n= 4 side dishes.

Total side dishes ordered = 5n = 20

She spent

$ 1.50 ( 4-1) = $ 4.5 each day or $22.5 on side dishes for 5 days.

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0